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7n^2+14n-76=-3
We move all terms to the left:
7n^2+14n-76-(-3)=0
We add all the numbers together, and all the variables
7n^2+14n-73=0
a = 7; b = 14; c = -73;
Δ = b2-4ac
Δ = 142-4·7·(-73)
Δ = 2240
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2240}=\sqrt{64*35}=\sqrt{64}*\sqrt{35}=8\sqrt{35}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-8\sqrt{35}}{2*7}=\frac{-14-8\sqrt{35}}{14} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+8\sqrt{35}}{2*7}=\frac{-14+8\sqrt{35}}{14} $
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